3b^2-12=3(b^2-4)

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Solution for 3b^2-12=3(b^2-4) equation:


Simplifying
3b2 + -12 = 3(b2 + -4)

Reorder the terms:
-12 + 3b2 = 3(b2 + -4)

Reorder the terms:
-12 + 3b2 = 3(-4 + b2)
-12 + 3b2 = (-4 * 3 + b2 * 3)
-12 + 3b2 = (-12 + 3b2)

Add '12' to each side of the equation.
-12 + 12 + 3b2 = -12 + 12 + 3b2

Combine like terms: -12 + 12 = 0
0 + 3b2 = -12 + 12 + 3b2
3b2 = -12 + 12 + 3b2

Combine like terms: -12 + 12 = 0
3b2 = 0 + 3b2
3b2 = 3b2

Add '-3b2' to each side of the equation.
3b2 + -3b2 = 3b2 + -3b2

Combine like terms: 3b2 + -3b2 = 0
0 = 3b2 + -3b2

Combine like terms: 3b2 + -3b2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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